Recap and Where We're Going
In the last lesson, you met three key formulas for finding the amount of substance, n (measured in moles):
- n = N / N_A — using the number of particles and Avogadro's constant (N_A = 6.02 × 10²³ mol⁻¹)
- n = m / M — using mass and molar mass
- n = V / V_m — using gas volume and molar volume (22.7 dm³ mol⁻¹ at STP, or 24.8 dm³ mol⁻¹ at SATP, depending on which conditions your syllabus data booklet specifies)
Today we combine these formulas with balanced chemical equations to solve real stoichiometry problems — converting between mass, particles, and gas volumes across a reaction (Talbot, p.418).
The General Strategy
Whatever combination of quantities you're given, the method is always the same three-step chain:
- Convert the given quantity (mass, particle number, or gas volume) into moles using the correct formula.
- Use the mole ratio from the balanced equation to find moles of the substance you want.
- Convert those moles into whatever quantity is asked for (mass, particles, or volume).
This mirrors the mass–mass method described by Talbot (p.424), just extended to particles and gases too.
Worked Example 1 – Mass to Gas Volume
Question: What volume of oxygen gas (at STP, V_m = 22.7 dm³ mol