Curriculum
Y1 · II · #30Stoichiometry – chemical calculations

Calculations using n = N/NA, n = m/M, n = V/Vm (I)

Introduction

The mole is the chemist's counting unit — it lets us link the invisible world of atoms and molecules to things we can actually measure, like mass and volume. In this lesson we look at three key equations that let you convert between number of particles, mass, and gas volume, and the amount of substance in moles (n). These three formulas are the backbone of almost every stoichiometry calculation you will do this year (Talbot, p.418).

The three key equations

1. Moles from number of particles

n = N / N_A
  • n = amount in moles
  • N = number of particles (atoms, molecules, ions...)
  • N_A = Avogadro's constant = 6.02 × 10²³ mol⁻¹

2. Moles from mass

n = m / M
  • m = mass in grams
  • M = molar mass in g mol⁻¹ (from the periodic table)

3. Moles from gas volume

n = V / V_m
  • V = volume of gas
  • V_m = molar volume of a gas (22.7 dm³ mol⁻¹ at STP, 100 kPa, 273 K)

Each formula can be rearranged to find any of the three variables, so it helps to remember them as a triangle: n is always "amount," and the other letter is whatever you're converting from.

Worked Example 1 – Using n = N/N_A

Question: How many moles are there in 3.01

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Source excerpts

From Chemistry for the IB Diploma 3e · Talbot

p.525relevance 12.4

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p.12relevance 11.8

Chemistry for the IB Diploma Programme x n Tool 3: Mathematics Skill Description Applying general mathematics • Use basic arithmetic and algebraic calculations to solve problems. • Carry out calculations involving decimals, fractions, percentages, ratios, r eciprocals and exponents. • Carry out calculations involving logarithmic functions. • Carry out calculations involving exp…

p.418relevance 11.4

R2: How much, how fast and how far? 406 How much? The amount of chemical changeR2.1 • How are chemical equations used to calculate reacting ratios? Guiding question SYLLABUS CONTENT By the end of this chapter, you should understand that:  chemical equations show the ratio of reactants and products in a reaction  the mole ratio of an equation can be used to determine:  the ma…

p.96relevance 11.4

84 S1: Models of the particulate nature of matter Calculate the percentage composition by mass of hydrated sodium sulfate, Na 2SO4.10H2O (M = 322 g mo l–1). Answer percentage by mass of sodium = 2 × 22.99 322 × 100 = 14.28% percentage by mass of sulfur = 32.07 322 × 100 = 9.96% percentage by mass of oxygen = 4 × 16.00 322 × 100 = 19.88% Note that this does not include the oxyge…

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + ATP
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