Curriculum
Y1 · II · #29Stoichiometry – chemical calculations

Amount of substance

Introduction

Chemists can't count atoms one by one — they're far too small and far too numerous. Instead, chemists use a special counting unit called the mole, which lets us connect the invisible world of atoms and molecules to things we can measure, like mass and volume. This lesson introduces the amount of substance and the key formulas you'll use throughout the stoichiometry unit.

The mole and Avogadro's constant

The mole (mol) is the SI unit for amount of substance, symbol n. One mole of any substance contains exactly the same number of particles: 6.02 × 10²³, known as the Avogadro constant (N_A).

  • 1 mole of carbon atoms = 6.02 × 10²³ carbon atoms
  • 1 mole of H₂O molecules = 6.02 × 10²³ H₂O molecules
  • 1 mole of Na⁺ ions = 6.02 × 10²³ Na⁺ ions

Molar mass

The molar mass (M), measured in g mol⁻¹, is the mass of one mole of a substance. You find it by adding up the relative atomic masses (from the periodic table) of all atoms in the formula.

Worked Example 1 Find the molar mass of Na₂SO₄·10H₂O.

M = (2 × 22.99) + 32.07 + (4 × 16.00) + 10 × [(2 × 1.01) + 16.00]
M = 45.98 + 32.07 + 64.00 + 180.00
M ≈ 322 g mol⁻¹

(Talbot, p. 96)

The key formula: n = m / M

Once you know the molar mass, you can convert between mass and amount using:

n = m / M

where n = amount (mol), m = mass (g), M = molar mass (g mol⁻¹).

Worked Example 2 How many moles of mercury(II) oxide are present in 1.25 g of H

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Source excerpts

From Chemistry for the IB Diploma 3e · Talbot

p.425relevance 15.4

R2.1 How much? The amount of chemical change 413 ■Mass–gas volume stoichiometry problems In a mass–volume stoichiometry problem, you will use a given mass of a reactant or product to determine an unknown volume of reactant or product. There are three steps: 1 Co nvert the mass of the given substance to an amount using the molar mass of the given s ubstance. 2 De termine the amo…

p.424relevance 14.8

R2: How much, how fast and how far? 412 Stoichiometry problems There are four basic types of stoichiometry problem involving the mole concept: ■ mass–mass ■ mass–gas volume ■ gas volume–gas volume ■ concentration. ■Mass–mass stoichiometry problems In a mass–mass stoichiometry problem, you will use a given mass of a reactant or product to determine an unknown mass of reactant or…

p.96relevance 10.7

84 S1: Models of the particulate nature of matter Calculate the percentage composition by mass of hydrated sodium sulfate, Na 2SO4.10H2O (M = 322 g mo l–1). Answer percentage by mass of sodium = 2 × 22.99 322 × 100 = 14.28% percentage by mass of sulfur = 32.07 322 × 100 = 9.96% percentage by mass of oxygen = 4 × 16.00 322 × 100 = 19.88% Note that this does not include the oxyge…

p.428relevance 10.3

R2: How much, how fast and how far? 416 Tool 3: Mathematics Express measurement and processed uncertainties – absolute, fractional (relative), percentage – to an appropriate number of significant figures or level of precision Measured uncertainties should be quoted as half the smallest division of the apparatus used to record them. Measurements made using the apparatus should t…

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + ATP
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